Solve the system.
-$$\begin{array} { c }
x - y + 3 z = 1 \
2 x + z = 0 \
x + 4 y + z = - 4
\end{array}$$
A) $\{ ( 0,0 , - 1 ) \}$
B) $\{ ( 0 , - 1,0 ) \}$
C) $\{ ( 0 , - 1,1 ) \}$
D) $\varnothing$

Question

Solve the system.
-$$\begin{array} { c } 
x - y + 3 z = 1 \
2 x + z = 0 \
x + 4 y + z = - 4
\end{array}$$
A) $\{ ( 0,0 , - 1 ) \}$
B) $\{ ( 0 , - 1,0 ) \}$
C) $\{ ( 0 , - 1,1 ) \}$
D) $\varnothing$

Quizplus · Accepted Answer

The Answer of Solve the system.
-$$\begin{array} { c } 
x - y + 3 z = 1 \
2 x + z = 0 \
x + 4 y + z = - 4
\end{array}$$
A) $\{ ( 0,0 , - 1 ) \}$
B) $\{ ( 0 , - 1,0 ) \}$
C) $\{ ( 0 , - 1,1 ) \}$
D) $\varnothing$

Solve the System x−y+3z=12x+z=0x+4y+z=−4\begin{array} { c } x - y + 3 z = 1 \\2 x + z = 0 \\x + 4 y + z = - 4\end{array}x−y+3z=12x+z=0x+4y+z=−4​

Solve the System $\begin{array} { c } x - y + 3 z = 1 \\2 x + z = 0 \\x + 4 y + z = - 4\end{array}$