Solve the System by Substitution $$\begin{array} { c } x - 3 y = 0 \\4 x - 3 y = - 18\end{array}$$

Solve the system by substitution.
- $$\begin{array} { c } x - 3 y = 0 \\4 x - 3 y = - 18\end{array}$$

A) $\{ ( - 6 , - 2 ) \}$
B) $\{ ( - 5 , - 3 ) \}$
C) $\varnothing$
D) $\{ ( 2 , - 6 ) \}$