Solve the Problem $\left\{ \begin{array} { l } 60 x + 60 y \geq 300 \\ 12 x + 6 y > 36 \\ 10 x + 30 y \geq 90 \end{array} \right.$

Solve the problem.
-The liquid portion of a diet is to provide at least 300 calories, 36 units of vitamin A, and 90 units of vitamin C daily. A cup of dietary drink X provides 60 calories, 12 units of vitamin A, and 10 units of vitamin C. A cup of
Dietary drink Y provides 60 calories, 6 units of vitamin A, and 30 units of vitamin C. Set up a system of linear
Inequalities that describes the minimum daily requirements for calories and vitamins. Let x = number of cups of
Dietary drink X, and y = number of cups of dietary drink Y. Write all the constraints as a system of linear
Inequalities.

A) $\left\{ \begin{array} { l } 60 x + 60 y \geq 300 \\ 12 x + 6 y > 36 \\ 10 x + 30 y \geq 90 \end{array} \right.$

B) $\left\{ \begin{array} { l } 60 x + 60 y \leq 300 \\ 12 x + 6 y \leq 36 \\ 10 x + 30 y \leq 90 \end{array} \right.$

C) $\left\{ \begin{array} { l } 60 x + 60 y > 3 \\ 12 x + 6 y > \\ 10 x + 30 y > \\ x > 0 \\ y > 0 \end{array} \right.$

D) $\left\{ \begin{array} { l } 60 x + 60 y \geq 300 \\ 12 x + 6 y \geq 36 \\ 10 x + 30 y \geq 90 \\ x \geq 0 \\ y \geq 0 \end{array} \right.$