Solve the problem.
-A person with no more than $3,000 to invest plans to place the money in two investments, telecommunications and pharmaceuticals. The telecommunications investment is to be no more than 4 times the pharmaceuticals
Investment. Write a system of inequalities to describe the situation. Let x = amount to be invested in
Telecommunications and y = amount to be invested in pharmaceuticals.
A)
$\begin{array}{l}
x+y=3,000 \
y \geq 4 x \
x \geq 0 \
y \geq 0
\end{array}$

B)
$\begin{array}{l}
x+y \leq 3,000 \
4 x \leq y \
x \geq 0 \
y \geq 0
\end{array}$

C)
$\begin{array}{l}
x+y \leq 3,000 \
x \leq 4 y \
x \geq 0 \
y \geq 0
\end{array}$

D)
$\begin{array}{l}
x+y=3,000 \
x \leq 4 y \
x \geq 0 \
y \geq 0
\end{array}$

Question

Solve the problem.
-A person with no more than $3,000 to invest plans to place the money in two investments, telecommunications and pharmaceuticals. The telecommunications investment is to be no more than 4 times the pharmaceuticals
Investment. Write a system of inequalities to describe the situation. Let x = amount to be invested in
Telecommunications and y = amount to be invested in pharmaceuticals.
A) 
$\begin{array}{l}
x+y=3,000 \
y \geq 4 x \
x \geq 0 \
y \geq 0
\end{array}$

B) 
$\begin{array}{l}
x+y \leq 3,000 \
4 x \leq y \
x \geq 0 \
y \geq 0
\end{array}$

C) 
$\begin{array}{l}
x+y \leq 3,000 \
x \leq 4 y \
x \geq 0 \
y \geq 0
\end{array}$

D) 
$\begin{array}{l}
x+y=3,000 \
x \leq 4 y \
x \geq 0 \
y \geq 0
\end{array}$

Quizplus · Accepted Answer

The total investment cannot exceed $3,000, so $x + y \leq 3,000$. The telecommunications investment (x) is to be no more than 4 times the pharmaceuticals investment (y), so $x \leq 4y$. Both investments must be non-negative, hence $x \geq 0$ and $y \geq 0$.

Solve the Problem x+y=3,000y≥4xx≥0y≥0\begin{array}{l}x+y=3,000 \\y \geq 4 x \\x \geq 0 \\y \geq 0\end{array}x+y=3,000y≥4xx≥0y≥0​

Solve the Problem $\begin{array}{l}x+y=3,000 \\y \geq 4 x \\x \geq 0 \\y \geq 0\end{array}$