Solve the problem.
-Suppose that certain bacteria can double their size and divide every 30 minutes. Write a recursive sequence that describes this growth where each value of n represents a 30-minute interval. Let $$\mathrm { a } _ { 1 } = 490$$ represent the initial
Number of bacteria present.
A) $a _ { n } = 2 a _ { 1 }$ for all values of $n$.
B) $a _ { 1 } = 490 ; a _ { n } = 2 a _ { n + 1 }$ for $n 1$.
C) $a _ { 1 } = 490 ; \quad a _ { n } = 2 a _ { n - 1 }$ for $n 1 .$
D) $a _ { 1 } = 490 ; \quad a _ { n } = \frac { 1 } { 2 } a _ { n - 1 }$ for $n 1$.

Question

Solve the problem.
-Suppose that certain bacteria can double their size and divide every 30 minutes. Write a recursive sequence that describes this growth where each value of n represents a 30-minute interval. Let $$\mathrm { a } _ { 1 } = 490$$ represent the initial
Number of bacteria present.
A) $a _ { n } = 2 a _ { 1 }$ for all values of $n$.
B) $a _ { 1 } = 490 ; a _ { n } = 2 a _ { n + 1 }$ for $n > 1$.
C) $a _ { 1 } = 490 ; \quad a _ { n } = 2 a _ { n - 1 }$ for $n > 1 .$
D) $a _ { 1 } = 490 ; \quad a _ { n } = \frac { 1 } { 2 } a _ { n - 1 }$ for $n > 1$.

Quizplus · Accepted Answer

The correct recursive sequence is $a _ { 1 } = 490 ; \quad a _ { n } = 2 a _ { n - 1 }$ for $n > 1$, as it accurately represents the bacteria doubling in size every 30 minutes.

Solve the Problem a1=490\mathrm { a } _ { 1 } = 490a1​=490

Solve the Problem $\mathrm { a } _ { 1 } = 490$