Solve the equation in the real number system.
-$3 x ^ { 3 } - 14 x ^ { 2 } + 13 x + 6 = 0$
A) $\{ - 1 , - 1 , - 2 \}$
B) $\left\{ \frac { 1 } { 3 } , 2 , - 3 \right\}$
C) $\left\{ - \frac { 1 } { 3 } , 2,3 \right\}$
D) $\{ 1 , - 1,2 \rangle$

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The Answer of Solve the equation in the real number system.
-$3 x ^ { 3 } - 14 x ^ { 2 } + 13 x + 6 = 0$
A) $\{ - 1 , - 1 , - 2 \}$
B) $\left\{ \frac { 1 } { 3 } , 2 , - 3 \right\}$
C) $\left\{ - \frac { 1 } { 3 } , 2,3 \right\}$
D) $\{ 1 , - 1,2 \rangle$

Solve the Equation in the Real Number System 3x3−14x2+13x+6=03 x ^ { 3 } - 14 x ^ { 2 } + 13 x + 6 = 03x3−14x2+13x+6=0

Solve the Equation in the Real Number System $3 x ^ { 3 } - 14 x ^ { 2 } + 13 x + 6 = 0$