Find the x- and y-intercepts of f.
-$f ( x ) = - x ^ { 2 } ( x + 3 ) \left( x ^ { 2 } + 1 \right)$
A) x-intercepts: -3, -1, 0, 1; y-intercept: 0
B) x-intercepts: -3, -1, 0; y-intercept: -3
C) x-intercepts: -3, 0; y-intercept: 0
D) x-intercepts: -3, -1, 0; y-intercept: 3

Question

Quizplus · Accepted Answer

To find the x-intercepts, set $f(x) = 0$. The equation becomes $-x^2(x + 3)(x^2 + 1) = 0$. The solutions to this equation are $x = 0$ and $x = -3$; $x^2 + 1 = 0$ has no real solutions because $x^2 + 1 > 0$ for all real x. To find the y-intercept, set $x = 0$ in $f(x)$, which gives $f(0) = 0$. Therefore, the x-intercepts are -3 and 0, and the y-intercept is 0.

Find the X- and Y-Intercepts of F f(x)=−x2(x+3)(x2+1)f ( x ) = - x ^ { 2 } ( x + 3 ) \left( x ^ { 2 } + 1 \right)f(x)=−x2(x+3)(x2+1)

Find the X- and Y-Intercepts of F $f ( x ) = - x ^ { 2 } ( x + 3 ) \left( x ^ { 2 } + 1 \right)$