Solve the problem using Snell's Law: $\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } }$
-A ray of light near the horizon with an angle of incidence of 77° enters a pool of water and strikes a fish's eye. If the index of refraction is 1.33, what is the angle of refraction (to two decimal places)?
A) 42.89°
B) 46.20°
C) 47.11°
D) 43.80°

Question

Quizplus · Accepted Answer

Using Snell's Law, $\sin \theta_2 = \frac{\sin 77°}{1.33}$. Solving gives $\theta_2 \approx 47.11°$.

Solve the Problem Using Snell's Law sin⁡θ1sin⁡θ2=v1v2\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } }sinθ2​sinθ1​​=v2​v1​​

Solve the Problem Using Snell's Law $\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } }$