Solve the equation on the interval [0, 2π).
-Suppose $f ( x ) = \cos \theta - 1$. Solve $f ( x ) = 0$.
A) $\frac { 3 \pi } { 2 }$
B) $\frac { \pi } { 2 }$
C) $\pi$
D) 0

Question

Quizplus · Accepted Answer

The equation $f(x) = \cos \theta - 1 = 0$ simplifies to $\cos \theta = 1$. The value of $\theta$ for which $\cos \theta = 1$ in the interval [0, 2π) is at $\theta = 0$.

Solve the Equation on the Interval [0, 2π) f(x)=cos⁡θ−1f ( x ) = \cos \theta - 1f(x)=cosθ−1

Solve the Equation on the Interval [0, 2π) $f ( x ) = \cos \theta - 1$