Use these equations to convert between the two systems. $C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32$ Round answer to the nearest tenth of a degree if necessary.
-Find the corresponding Celsius temperature for a temperature of 242°F. Round to the nearest tenth, if necessary.
A) $467.6 ^ { \circ } \mathrm { C }$
B) $116.7 ^ { \circ } \mathrm { C }$
C) $130.9 ^ { \circ } \mathrm { C }$
D) $378 ^ { \circ } \mathrm { C }$

Question

Use these equations to convert between the two systems. $C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32$ Round answer to the nearest tenth of a degree if necessary.
-Find the corresponding Celsius temperature for a temperature of 242°F. Round to the nearest tenth, if necessary. 
A) $467.6 ^ { \circ } \mathrm { C }$
B) $116.7 ^ { \circ } \mathrm { C }$
C) $130.9 ^ { \circ } \mathrm { C }$
D) $378 ^ { \circ } \mathrm { C }$

Quizplus · Accepted Answer

To convert 242°F to Celsius, use the formula $C = \frac { 5 } { 9 } ( F - 32 )$. Plugging in 242 for F gives $C = \frac { 5 } { 9 } ( 242 - 32 ) = \frac { 5 } { 9 } \times 210 = 116.7 ^ { \circ } \mathrm { C }$.

Use These Equations to Convert Between the Two Systems C=59(F−32)F=95C+32C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32C=95​(F−32)F=59​C+32

Use These Equations to Convert Between the Two Systems $C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32$