Use these equations to convert between the two systems. $C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32$ Round answer to the nearest tenth of a degree if necessary.
-$$\mathrm { F } = 229 ^ { \circ }$$
A) $C = 354.6 ^ { \circ }$
B) $C = 123.7 ^ { \circ }$
C) $C = 444.2 ^ { \circ }$
D) $C = 109.4 ^ { \circ }$

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The Answer of Use these equations to convert between the two systems. $C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32$ Round answer to the nearest tenth of a degree if necessary.
-$$\mathrm { F } = 229 ^ { \circ }$$
A) $C = 354.6 ^ { \circ }$
B) $C = 123.7 ^ { \circ }$
C) $C = 444.2 ^ { \circ }$
D) $C = 109.4 ^ { \circ }$

Use These Equations to Convert Between the Two Systems C=59(F−32)F=95C+32C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32C=95​(F−32)F=59​C+32

Use These Equations to Convert Between the Two Systems $C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32$