Use the summation properties to evaluate the series. The following rules may be needed: $$\sum _ { i = 1 } ^ { n } i = \frac { n ( n + 1 ) } { 2 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 }$$
-$$\sum _ { i = 1 } ^ { 5 } \left( 3 + 2 i ^ { 3 } \right)$$
A) 685
B) 465
C) 1125
D) 915

Question

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The Answer of Use the summation properties to evaluate the series. The following rules may be needed: $$\sum _ { i = 1 } ^ { n } i = \frac { n ( n + 1 ) } { 2 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 }$$
-$$\sum _ { i = 1 } ^ { 5 } \left( 3 + 2 i ^ { 3 } \right)$$
A) 685
B) 465
C) 1125
D) 915

Use the Summation Properties to Evaluate the Series - ∑i=15(3+2i3)\sum _ { i = 1 } ^ { 5 } \left( 3 + 2 i ^ { 3 } \right)i=1∑5​(3+2i3)

Use the Summation Properties to Evaluate the Series - $\sum _ { i = 1 } ^ { 5 } \left( 3 + 2 i ^ { 3 } \right)$