Use the Summation Properties to Evaluate the Series - $$\sum _ { i = 1 } ^ { 6 } 3 i$$

Use the summation properties to evaluate the series. The following rules may be needed: $$\sum _ { i = 1 } ^ { n } i = \frac { n ( n + 1 ) } { 2 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 2 } = \frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 } ; \quad \sum _ { i = 1 } ^ { n } i ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 }$$
- $$\sum _ { i = 1 } ^ { 6 } 3 i$$

A) $\frac { 63 } { 2 }$
B) 171
C) $\frac { 63 } { 4 }$
D) 63