Find the Power of a Quotient
-$\left( \frac { 2 x ^ { 3 } } { y ^ { 2 } } \right) ^ { - 3 }$
A) $\frac { y ^ { 6 } } { 8 x ^ { 9 } }$
B) $\frac { 8 x ^ { 9 } } { y ^ { 6 } }$
C) $\frac { 8 y ^ { 6 } } { x ^ { 9 } }$
D) $\frac { y ^ { 2 } } { 8 x ^ { 9 } }$

Question

Quizplus · Accepted Answer

When raising a quotient to a negative exponent, you flip the numerator and denominator and change the sign of the exponent. Thus, $\left( \frac { 2 x ^ { 3 } } { y ^ { 2 } } \right) ^ { - 3 } = \left( \frac { y ^ { 2 } } { 2 x ^ { 3 } } \right) ^ { 3 }$. Applying the power to both the numerator and denominator, $y^{2*3}$ becomes $y^6$ and $2^3 x^{3*3}$ becomes $8x^9$, resulting in $\frac { y ^ { 6 } } { 8 x ^ { 9 } }$.

Find the Power of a Quotient - (2x3y2)−3\left( \frac { 2 x ^ { 3 } } { y ^ { 2 } } \right) ^ { - 3 }(y22x3​)−3

Find the Power of a Quotient
- $\left( \frac { 2 x ^ { 3 } } { y ^ { 2 } } \right) ^ { - 3 }$