Parametric Equations
1 Use Point Plotting to Graph Plane Curves Described by Parametric Equations
-$x = \left( 40 \cos 30 ^ { \circ } \right) t , y = 6 + \left( 40 \sin 30 ^ { \circ } \right) t - 10 t ^ { 2 } ; t = 6$
A) $( 120 \sqrt { 3 } , - 234 )$
B) $( 240 \sqrt { 3 } , 220 )$
C) $( 120 \sqrt { 3 } , 66 )$
D) $( - 120 \sqrt { 3 } , 172 )$

Question

Quizplus · Accepted Answer

To find the coordinates at $t = 6$, substitute $t$ into the given parametric equations. For $x$, $x = (40 \cos 30^\circ) \cdot 6 = 40 \cdot \sqrt{3}/2 \cdot 6 = 120\sqrt{3}$. For $y$, $y = 6 + (40 \sin 30^\circ) \cdot 6 - 10 \cdot 6^2 = 6 + 20 \cdot 6 - 360 = 6 + 120 - 360 = -234$. Therefore, the coordinates are $(120\sqrt{3}, -234)$.

Parametric Equations 1 Use Point Plotting to Graph Plane Curves x=(40cos⁡30∘)t,y=6+(40sin⁡30∘)t−10t2;t=6x = \left( 40 \cos 30 ^ { \circ } \right) t , y = 6 + \left( 40 \sin 30 ^ { \circ } \right) t - 10 t ^ { 2 } ; t = 6x=(40cos30∘)t,y=6+(40sin30∘)t−10t2;t=6

Parametric Equations
1 Use Point Plotting to Graph Plane Curves $x = \left( 40 \cos 30 ^ { \circ } \right) t , y = 6 + \left( 40 \sin 30 ^ { \circ } \right) t - 10 t ^ { 2 } ; t = 6$