Parametric Equations
1 Use Point Plotting to Graph Plane Curves Described by Parametric Equations
-$x = t ^ { 2 } + 1 , y = 6 - t ^ { 3 } ; t = 2$
A) $( 5 , - 2 )$
B) $( 5,14 )$
C) $( 10 , - 7 )$
D) $( 10,0 )$

Question

Quizplus · Accepted Answer

To find the coordinates of the point when $t = 2$, substitute $t = 2$ into the given parametric equations. For $x$, $x = 2^2 + 1 = 5$. For $y$, $y = 6 - 2^3 = 6 - 8 = -2$. Therefore, the point is $(5, -2)$.

Parametric Equations 1 Use Point Plotting to Graph Plane Curves x=t2+1,y=6−t3;t=2x = t ^ { 2 } + 1 , y = 6 - t ^ { 3 } ; t = 2x=t2+1,y=6−t3;t=2

Parametric Equations
1 Use Point Plotting to Graph Plane Curves $x = t ^ { 2 } + 1 , y = 6 - t ^ { 3 } ; t = 2$