Find the center (h, k) and radius r of the circle with the given equation.
-$$3 ( x + 2 ) ^ { 2 } + 3 ( y + 3 ) ^ { 2 } = 36$$
A) $( \mathrm { h } , \mathrm { k } ) = ( - 2 , - 3 ) ; \mathrm { r } = 6 \sqrt { 3 }$
B) $( h , k ) = ( 2,3 ) ; r = 6 \sqrt { 3 }$
C) $( \mathrm { h } , \mathrm { k } ) = ( - 2 , - 3 ) ; \mathrm { r } = 2 \sqrt { 3 }$
D) $( h , k ) = ( 2,3 ) ; r = 2 \sqrt { 3 }$

Question

Quizplus · Accepted Answer

The equation can be rewritten as $(x + 2)^2 + (y + 3)^2 = 12$ by dividing by 3. The center is $(-2, -3)$ and the radius is $\sqrt{12} = 2\sqrt{3}$.

Find the Center (H, K) and Radius R of the Circle