Find the center (h, k) and radius r of the circle with the given equation.
-$$x ^ { 2 } + ( y + 6 ) ^ { 2 } = 9$$
A) $( \mathrm { h } , \mathrm { k } ) = ( 0 , - 6 ) ; \mathrm { r } = 9$
B) $( \mathrm { h } , \mathrm { k } ) = ( - 6,0 ) ; \mathrm { r } = 9$
C) $( \mathrm { h } , \mathrm { k } ) = ( - 6,0 ) ; \mathrm { r } = 3$
D) $( \mathrm { h } , \mathrm { k } ) = ( 0 , - 6 ) ; \mathrm { r } = 3$

Question

Quizplus · Accepted Answer

The standard form of a circle's equation is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. Comparing the given equation $x^2 + (y + 6)^2 = 9$ to the standard form, we find $h = 0$, $k = -6$, and $r^2 = 9$, which means $r = 3$.

Find the Center (H, K) and Radius R of the Circle