Find the center (h, k) and radius r of the circle with the given equation.
-$$( x + 5 ) ^ { 2 } + ( y + 6 ) ^ { 2 } = 144$$
A) $( h , k ) = ( - 5 , - 6 ) ; r = 12$
B) $( h , k ) = ( - 5 , - 6 ) ; r = 144$
C) $( h , k ) = ( - 6 , - 5 ) ; r = 144$
D) $( \mathrm { h } , \mathrm { k } ) = ( - 6 , - 5 ) ; \mathrm { r } = 12$

Question

Quizplus · Accepted Answer

The equation of a circle in the standard form is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. Given equation $(x + 5)^2 + (y + 6)^2 = 144$ matches this form with $h = -5$, $k = -6$, and $r^2 = 144$, so $r = 12$.

Find the Center (H, K) and Radius R of the Circle