Write the standard form of the equation of the circle with radius r and center (h, k).
-$$\mathrm { r } = \sqrt { 7 } ; ( \mathrm { h } , \mathrm { k } ) = ( 0 , - 6 )$$
A) $( x - 6 ) ^ { 2 } + y ^ { 2 } = 49$
B) $x ^ { 2 } + ( y + 6 ) ^ { 2 } = 7$
C) $( x + 6 ) ^ { 2 } + y ^ { 2 } = 49$
D) $x ^ { 2 } + ( y - 6 ) ^ { 2 } = 7$

Question

Quizplus · Accepted Answer

The standard form of the equation of a circle is $(x - h)^2 + (y - k)^2 = r^2$. Given $r = \sqrt{7}$, $h = 0$, and $k = -6$, the equation becomes $x^2 + (y + 6)^2 = 7$.

Write the Standard Form of the Equation of the Circle r=7;(h,k)=(0,−6)\mathrm { r } = \sqrt { 7 } ; ( \mathrm { h } , \mathrm { k } ) = ( 0 , - 6 )r=7​;(h,k)=(0,−6)

Write the Standard Form of the Equation of the Circle $\mathrm { r } = \sqrt { 7 } ; ( \mathrm { h } , \mathrm { k } ) = ( 0 , - 6 )$