Solve f(x) = g(x). Find the points of intersection of the graphs of the two functions.
-$$\begin{array} { l }
f ( x ) = x ^ { 2 } + 6 x + 23 \
g ( x ) = 23
\end{array}$$
A) $x = 0 , x = 6$
B) $x = - 6 , x = 0$
C) $ \mathrm { x } = \frac { 6 \pm \sqrt { 23 } } { 2 }$
D) no real numbers

Question

Solve f(x) = g(x). Find the points of intersection of the graphs of the two functions.
-$$\begin{array} { l } 
f ( x ) = x ^ { 2 } + 6 x + 23 \
g ( x ) = 23
\end{array}$$
A) $x = 0 , x = 6$
B) $x = - 6 , x = 0$
C) $ \mathrm { x } = \frac { 6 \pm \sqrt { 23 } } { 2 }$
D) no real numbers

Quizplus · Accepted Answer

To find the points of intersection, set $f(x) = g(x)$: $x^2 + 6x + 23 = 23$. Simplifying gives $x^2 + 6x = 0$, which factors to $x(x + 6) = 0$. Thus, $x = 0$ or $x = -6$.

Solve F(x) = G(x) f(x)=x2+6x+23g(x)=23\begin{array} { l } f ( x ) = x ^ { 2 } + 6 x + 23 \\g ( x ) = 23\end{array}f(x)=x2+6x+23g(x)=23​

Solve F(x) = G(x) $\begin{array} { l } f ( x ) = x ^ { 2 } + 6 x + 23 \\g ( x ) = 23\end{array}$