Solve f(x) = g(x). Find the points of intersection of the graphs of the two functions.
-$$\begin{array} { l }
f ( x ) = 13 x ^ { 2 } \
g ( x ) = - 3 x
\end{array}$$
A) $x = \frac { 3 } { 13 } , x = 0$
B) $x = - \frac { 3 } { 13 } , x = 0$
C) $x = \pm \frac { 3 } { 13 }$
D) $x = 0$

Question

Solve f(x) = g(x). Find the points of intersection of the graphs of the two functions.
-$$\begin{array} { l } 
f ( x ) = 13 x ^ { 2 } \
g ( x ) = - 3 x
\end{array}$$
A) $x = \frac { 3 } { 13 } , x = 0$
B) $x = - \frac { 3 } { 13 } , x = 0$
C) $x = \pm \frac { 3 } { 13 }$
D) $x = 0$

Quizplus · Accepted Answer

To find the points of intersection, set $f(x) = g(x)$: $13x^2 = -3x$. Rearrange to $13x^2 + 3x = 0$. Factor to $x(13x + 3) = 0$. Solutions are $x = 0$ and $x = -\frac{3}{13}$.

Solve F(x) = G(x) f(x)=13x2g(x)=−3x\begin{array} { l } f ( x ) = 13 x ^ { 2 } \\g ( x ) = - 3 x\end{array}f(x)=13x2g(x)=−3x​

Solve F(x) = G(x) $\begin{array} { l } f ( x ) = 13 x ^ { 2 } \\g ( x ) = - 3 x\end{array}$