Solve the problem.
-The path of a projectile fired at an inclination θ to the horizontal with an initial speed vo is a parabola. The range R of the projectile, the horizontal distance that the projectile travels, is found by the formula
Feet per second per second or g = 9.8 meters per second per second. Find the $\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } } \text { where } \mathrm { g } = 32.2$ range of a projectile fired with an initial velocity of 174 feet per second at an angle of 35° to the horizontal.
Round your answer to two decimal places.
A) 883.54 ft
B) 883.44 ft
C) 1,078.61 ft
D) 539.30 ft

Question

Quizplus · Accepted Answer

To find the range $R$, we use the formula $R = \frac{v_0^2 \sin 2\theta}{g}$, where $v_0 = 174$ ft/s, $\theta = 35^\circ$, and $g = 32.2$ ft/s$^2$. Plugging these values into the formula gives $R = \frac{174^2 \sin(2 \times 35)}{32.2}$, which calculates to approximately 883.54 ft when rounded to two decimal places.

Solve the Problem R=vO2sin⁡2θg where g=32.2\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } } \text { where } \mathrm { g } = 32.2R=gvO2​sin2θ​ where g=32.2

Solve the Problem $\mathrm { R } = \frac { \mathrm { v } _ { \mathrm { O } } ^ { 2 } \sin 2 \theta } { \mathrm { g } } \text { where } \mathrm { g } = 32.2$