Solve the problem.
-If friction is ignored, the time t (in seconds) required for a block to slide down an inclined plane is given by the formula $t = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } }$ where a is the length (in feet) of the base and g =32 feet per second per second is the acceleration of gravity. How long does it take a block to slide down an inclined plane with base a = 12 when θ = 58°? If necessary, round the
Answer to the nearest tenth of a second.
A) 1.5 sec
B) 1.4 sec
C) 0.5 sec
D) 1.6 sec

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The Answer of Solve the problem.
-If friction is ignored, the time t (in seconds) required for a block to slide down an inclined plane is given by the formula $t = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } }$ where a is the length (in feet) of the base and g =32 feet per second per second is the acceleration of gravity. How long does it take a block to slide down an inclined plane with base a = 12 when θ = 58°? If necessary, round the
Answer to the nearest tenth of a second.
A) 1.5 sec
B) 1.4 sec
C) 0.5 sec
D) 1.6 sec

Solve the Problem t=2agsin⁡θcos⁡θt = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } }t=gsinθcosθ2a​​

Solve the Problem $t = \sqrt { \frac { 2 a } { g \sin \theta \cos \theta } }$