Solve for the indicated variable.
-$\log _ { c } ( z + y ) = \log _ { c } ( 2 z - 4 )$, for $y$
A) $y = \frac { \log _ { \mathrm { c } } \mathrm { z } } { 4 }$
B) $y = \log _ { c } ( z - 4 )$
C) $y = z - 4$
D) $y = \frac { z } { 4 }$

Question

Quizplus · Accepted Answer

Given $\log_c(z + y) = \log_c(2z - 4)$, by the property of logarithms, if $\log_c(A) = \log_c(B)$, then $A = B$. Therefore, $z + y = 2z - 4$. Solving for $y$ gives $y = z - 4$.

Solve for the Indicated Variable log⁡c(z+y)=log⁡c(2z−4)\log _ { c } ( z + y ) = \log _ { c } ( 2 z - 4 )logc​(z+y)=logc​(2z−4)

Solve for the Indicated Variable $\log _ { c } ( z + y ) = \log _ { c } ( 2 z - 4 )$