Solve for the indicated variable.
-$\mathrm { D } = \mathrm { D } _ { 0 } \mathrm { e } ^ { \mathrm { kt } / 800 , }$, for $\mathrm { t }$
A) $t = \frac { 800 \mathrm { D } } { \mathrm { kD } _ { 0 } }$
B) $t = \frac { 800 } { k } \ln \frac { D } { D _ { 0 } }$
C) $t = \frac { 800 } { k } \ln \left( D - D _ { 0 } \right)$
D) $t = \frac { k } { 800 } \ln \frac { D } { D _ { 0 } }$

Question

Quizplus · Accepted Answer

To solve for $t$, divide both sides by $D_0$ to get $\frac{D}{D_0} = e^{kt/800}$. Then, take the natural logarithm of both sides to isolate $t$, resulting in $t = \frac{800}{k} \ln \frac{D}{D_0}$.

Solve for the Indicated Variable D=D0ekt/800,\mathrm { D } = \mathrm { D } _ { 0 } \mathrm { e } ^ { \mathrm { kt } / 800 , }D=D0​ekt/800,

Solve for the Indicated Variable $\mathrm { D } = \mathrm { D } _ { 0 } \mathrm { e } ^ { \mathrm { kt } / 800 , }$