Find all cube roots of the complex number. Leave answers in trigonometric form.
-$125 \mathrm { i }$
A) 5 cis $0 ^ { \circ } , 5 \operatorname { cis } 120 ^ { \circ } , 5$ cis $240 ^ { \circ }$
B) $5 \operatorname { cis } 60 ^ { \circ } , 5 \operatorname { cis } 180 ^ { \circ } , 5 \operatorname { cis } 300 ^ { \circ }$
C) $1 , - 1 , - \mathrm { i }$
D) $5 \operatorname { cis } 30 ^ { \circ } , 5 \operatorname { cis } 150 ^ { \circ } , 5 \operatorname { cis } 270 ^ { \circ }$

Question

Quizplus · Accepted Answer

The complex number $125i$ can be expressed in polar form as $125 \operatorname{cis} 90^\circ$. The cube roots will have a magnitude of $5$ and angles $30^\circ, 150^\circ, 270^\circ$.

Find All Cube Roots of the Complex Number 125i125 \mathrm { i }125i

Find All Cube Roots of the Complex Number $125 \mathrm { i }$