Solve the equation for y.
-The temperature of water in a certain lake on a day in October can be determined by using the model $y = 15.2 - 0.537 x$ where x is the number of feet down from the surface of the lake and y is the Celsius temperature of the water at that depth. Based on this model, how deep in the lake is the water 8 degrees? Round
To the nearest foot.
A) 69 ft
B) 32 ft
C) 43 ft
D) 13 ft

Question

Quizplus · Accepted Answer

To find the depth at which the water is 8 degrees Celsius, set $y = 8$ and solve for $x$: $8 = 15.2 - 0.537x$. Rearranging gives $0.537x = 15.2 - 8$, so $x = \frac{7.2}{0.537} \approx 13.41$. Rounded to the nearest foot, $x = 13$ ft.

Solve the Equation for Y y=15.2−0.537xy = 15.2 - 0.537 xy=15.2−0.537x

Solve the Equation for Y $y = 15.2 - 0.537 x$