Solve the equation exactly in the complex number system.
-$6 x ^ { 3 } + 6 x = 0$
A) $x = - 6 , x = \pm i$
B) $x = 0 , x = \pm i$
C) $x = \pm i$
D) $x = 0 , x = \pm 1$

Question

Quizplus · Accepted Answer

First, factor out the common term, which gives $6x(x^2 + 1) = 0$. Setting each factor equal to zero gives the solutions: $x = 0$ and $x^2 + 1 = 0$, which leads to $x = \pm i$.

Solve the Equation Exactly in the Complex Number System 6x3+6x=06 x ^ { 3 } + 6 x = 06x3+6x=0

Solve the Equation Exactly in the Complex Number System $6 x ^ { 3 } + 6 x = 0$