Solve the equation exactly in the complex number system.
-$$x ^ { 3 } + 4 x ^ { 2 } - 2 x - 8 = 0$$
A) $x = - \sqrt { 4 } , x = \pm 2$
B) $x = - 4 , x = \pm 2$
C) $x = - 4 , x = \pm \sqrt { 2 }$
D) $x = - \sqrt { 4 } , x = \pm \sqrt { 2 }$

Question

Quizplus · Accepted Answer

The equation can be factored as $(x + 4)(x^2 - 2) = 0$, giving roots $x = -4$ and $x = \pm \sqrt{2}$.

Solve the Equation Exactly in the Complex Number System x3+4x2−2x−8=0x ^ { 3 } + 4 x ^ { 2 } - 2 x - 8 = 0x3+4x2−2x−8=0

Solve the Equation Exactly in the Complex Number System $x ^ { 3 } + 4 x ^ { 2 } - 2 x - 8 = 0$