Solve the polynomial equation by factoring.
-$$x ^ { 3 } - 16 x = 0$$
A) $4 , - 4$
B) $0,4 , - 4$
C) $8 , - 8$
D) $0,8 , - 8$

Name: Solve the polynomial equation by factoring. -\[x ^ { 3 } - 16 x = 0\] A) $4 , - 4$ B) $0,4 , - 4$ C) $8 , - 8$ D) $0,8 , - 8$
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Question

Quizplus · Accepted Answer

First, factor out an $x$, getting $x(x^2 - 16) = 0$. Then, notice $x^2 - 16$ is a difference of squares, so it factors further into $(x + 4)(x - 4)$. Setting each factor equal to zero gives the solutions $x = 0$, $x = 4$, and $x = -4$.

Solve the Polynomial Equation by Factoring x3−16x=0x ^ { 3 } - 16 x = 0x3−16x=0

Solve the Polynomial Equation by Factoring $x ^ { 3 } - 16 x = 0$