$\begin{array}{l|rrrrr}
x & -3 & -2 & -1 & 2 & 4 \
\mathrm{y} \mid & -3 & 3 & 5 & 9 & 12
\end{array} \text { (Quartic) }$

A) $y = - 0.05 x ^ { 4 } + 0.18 x ^ { 3 } + 0.25 x ^ { 2 } + 0.80 x + 5.77$
B) $y = 0.05 x ^ { 4 } - 0.18 x ^ { 3 } + 0.25 x ^ { 2 } + 0.80 x + 5.77$
C) $y = - 0.05 x ^ { 4 } + 0.12 x ^ { 3 } - 0.24 x ^ { 2 } - 0.80 x + 5.77$
D) $y = - 0.05 x ^ { 4 } + 0.12 x ^ { 3 } + 0.24 x ^ { 2 } + 0.80 x + 5.75$

Question

$\begin{array}{l|rrrrr}
x & -3 & -2 & -1 & 2 & 4 \
\mathrm{y} \mid & -3 & 3 & 5 & 9 & 12
\end{array} \text { (Quartic) }$

A) $y = - 0.05 x ^ { 4 } + 0.18 x ^ { 3 } + 0.25 x ^ { 2 } + 0.80 x + 5.77$
B) $y = 0.05 x ^ { 4 } - 0.18 x ^ { 3 } + 0.25 x ^ { 2 } + 0.80 x + 5.77$
C) $y = - 0.05 x ^ { 4 } + 0.12 x ^ { 3 } - 0.24 x ^ { 2 } - 0.80 x + 5.77$
D) $y = - 0.05 x ^ { 4 } + 0.12 x ^ { 3 } + 0.24 x ^ { 2 } + 0.80 x + 5.75$

Quizplus · Accepted Answer

Given the table of values and the fact that the relationship is quartic (involving a term of $x^4$), we can determine the correct equation by plugging in the values of $x$ from the table into each equation and checking which one yields the corresponding $y$ values. Option A is the correct equation because it accurately represents the relationship between $x$ and $y$ as given in the table.

x−3−2−124y∣−335912 (Quartic) \begin{array}{l|rrrrr}x & -3 & -2 & -1 & 2 & 4 \\\mathrm{y} \mid & -3 & 3 & 5 & 9 & 12\end{array} \text { (Quartic) }xy∣​−3−3​−23​−15​29​412​ (Quartic)

$\begin{array}{l|rrrrr}x & -3 & -2 & -1 & 2 & 4 \\\mathrm{y} \mid & -3 & 3 & 5 & 9 & 12\end{array} \text { (Quartic) }$