Use the definition of big_$O$ to prove that $\frac { 6 n + 4 n ^ { 5 } - 4 } { 7 n ^ { 2 } - 3 }$ is $O \left( n ^ { 3 } \right)$.

Name: Use the definition of big_$O$ to prove that $\frac { 6 n + 4 n ^ { 5 } - 4 } { 7 n ^ { 2 } - 3 }$ is $O \left( n ^ { 3 } \right)$.
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\left| \frac { 6 n + 4 n ^ { 5 } - 4 } { 7 n ^ { 2 } - 3 } ight| \leq \left| \frac { 6 n ^ { 5 } + 4 n ^ { 5 } } { 7 n ^ { 2 } - n ^ { 2 } } ight| = \left| \frac { 10 n ^ { 5 } } { 6 n ^ { 2 } } ight| = \frac { 5 } { 3 } \left| n ^ { 3 } ight| , ext { if } n \geq 2

Use the Definition of Big_ OOO To Prove That 6n+4n5−47n2−3\frac { 6 n + 4 n ^ { 5 } - 4 } { 7 n ^ { 2 } - 3 }7n2−36n+4n5−4​

Use the Definition of Big_ $O$ To Prove That $\frac { 6 n + 4 n ^ { 5 } - 4 } { 7 n ^ { 2 } - 3 }$