Find the domain of the rational function.
$f ( x ) = \frac { x ^ { 2 } - 64 } { x ^ { 2 } - 7 x + 10 }$
A) $\{ x \mid x \text { is a real number and } x \neq - 2 , x \neq - 5 \}$
B) $\{ x \mid x \text { is a real number and } x \neq 2 , x \neq 5 \}$
C) $\{ x \mid x \text { is a real number and } x \neq 8 , x \neq - 8 \}$
D) $\{ x \mid x \text { is a real number and } x \neq 0 \}$

Question

Quizplus · Accepted Answer

The domain of a rational function is all real numbers except where the denominator equals zero. Factoring the denominator $x^2 - 7x + 10 = (x-2)(x-5)$, we find that the function is undefined at $x = 2$ and $x = 5$, hence the correct domain is all real numbers except $x \neq 2$ and $x \neq 5$.

Find the Domain of the Rational Function f(x)=x2−64x2−7x+10f ( x ) = \frac { x ^ { 2 } - 64 } { x ^ { 2 } - 7 x + 10 }f(x)=x2−7x+10x2−64​

Find the Domain of the Rational Function $f ( x ) = \frac { x ^ { 2 } - 64 } { x ^ { 2 } - 7 x + 10 }$