Find the domain of the rational function.
$f ( r ) = \frac { r ^ { 2 } + 24 r } { 6 r }$
A) $\left\{ \mathrm { r } \mid \mathrm { r } \text { is a real number and } \mathrm { r } \neq \frac { 1 } { 6 } \right\}$
B) $\{ r \mid r \text { is a real number and } r \neq 0 \text { and } r \neq - 24 \}$
C) $\{ \mathrm { r } \mid \mathrm { r } \text { is a real number and } \mathrm { r } \neq 6 \}$
D) $\{ \mathrm { r } \mid \mathrm { r } \text { is a real number and } \mathrm { r } \neq 0 \}$

Question

Quizplus · Accepted Answer

The domain of a rational function includes all real numbers except those that make the denominator equal to zero. In this case, the denominator is $6r$, which is equal to zero when $r = 0$. Therefore, the domain is all real numbers except $r = 0$.

Find the Domain of the Rational Function f(r)=r2+24r6rf ( r ) = \frac { r ^ { 2 } + 24 r } { 6 r }f(r)=6rr2+24r​

Find the Domain of the Rational Function $f ( r ) = \frac { r ^ { 2 } + 24 r } { 6 r }$