Solve.
-A city is growing at the rate of 0.8% annually. If there were 3,917,000 residents in the city in 1994, find how many (to the nearest ten-thousand) are living in that city in 2000 $$\text { Use } y = 3,917,000 ( 2.7 ) ^ { 0.008 t } \text {. }$$
A) 10,580,000
B) 510,000
C) 4,140,000
D) 4,110,000

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The Answer of Solve.
-A city is growing at the rate of 0.8% annually. If there were 3,917,000 residents in the city in 1994, find how many (to the nearest ten-thousand) are living in that city in 2000 $$\text { Use } y = 3,917,000 ( 2.7 ) ^ { 0.008 t } \text {. }$$
A) 10,580,000
B) 510,000
C) 4,140,000
D) 4,110,000

Solve -A City Is Growing at the Rate of 0 Use y=3,917,000(2.7)0.008t. \text { Use } y = 3,917,000 ( 2.7 ) ^ { 0.008 t } \text {. } Use y=3,917,000(2.7)0.008t.

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-A City Is Growing at the Rate of 0 $\text { Use } y = 3,917,000 ( 2.7 ) ^ { 0.008 t } \text {. }$