Solve.
-Four bacteria are placed in a petri dish. The population will double every day. The formula for the number of bacteria in the dish on day t is $$\mathrm { N } ( \mathrm { t } ) = 4 ( 2 ) ^ { \mathrm { t } }$$ where t is the number of days after the four bacteria are placed in the dish. How many bacteria are in the dish six
Days after the four bacteria are placed in the dish?
A) 144
B) 256
C) 12
D) 48

Question

Quizplus · Accepted Answer

To find the number of bacteria in the dish six days after the initial placement, substitute $t = 6$ into the given formula: $\mathrm{N}(6) = 4(2)^6 = 4 \times 64 = 256$.

Solve -Four Bacteria Are Placed in a Petri Dish N(t)=4(2)t\mathrm { N } ( \mathrm { t } ) = 4 ( 2 ) ^ { \mathrm { t } }N(t)=4(2)t

Solve
-Four Bacteria Are Placed in a Petri Dish $\mathrm { N } ( \mathrm { t } ) = 4 ( 2 ) ^ { \mathrm { t } }$