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# Quiz 7: Confidence Intervals

Use the normal approximation to find the indicated probability. The sample size is n , the population proportion of successes is p , and X is the number of successes in the sample. $n = 83 , p = 0.35 : P ( X \leq 27 )$
(Multiple Choice)
At a cell phone assembly plant, 77% of the cell phone keypads pass inspection. A random sample of 111 keypads is analysed. Find the probability that the proportion of the sample keypads that pass inspection is between 0.72 and 0.8
(Multiple Choice)
At a cell phone assembly plant, 81% of the cell phone keypads pass inspection. A random sample of 97 keypads is analysed. Find the probability that more than 85% of the sample keypads pass inspection.
(Multiple Choice)
At a cell phone assembly plant, 77% of the cell phone keypads pass inspection. A random sample of 98 keypads is analysed. Find the mean
(Multiple Choice)
A gardener buys a package of seeds. Seventy-five percent of seeds of this type germinate. The gardener plants 90 seeds. Approximate the probability that the number of seeds that germinate is between 57.5 and 72.5 exclusive.
(Multiple Choice)
A gardener buys a package of seeds. Eighty-two percent of seeds of this type germinate. The gardener plants 130 seeds. Approximate the probability that 99 or more seeds germinate.
(Multiple Choice)
Use the normal approximation to find the indicated probability. The sample size is n , the population proportion of successes is p , and X is the number of successes in the sample. $n = 86 , p = 0.68 : P ( 54 \leq X \leq 61 )$
(Multiple Choice)
A gardener buys a package of seeds. Eighty-five percent of seeds of this type germinate. The gardener plants 110 seeds. Approximate the probability that fewer than 85 seeds germinate.
(Multiple Choice)
For a particular diamond mine, 77% of the diamonds fail to qualify as "gemstone grade". A random sample of 112 diamonds is analysed. Find the probability that more than 81% of the sample diamonds fail to qualify as gemstone grade.
(Multiple Choice)
Use the normal approximation to find the indicated probability. The sample size is n , the population proportion of successes is p , and X is the number of successes in the sample. $n = 94 , p = 0.65 : P ( X < 67 )$
(Multiple Choice)
For a particular diamond mine, 75% of the diamonds fail to qualify as "gemstone grade". A random sample of 110 diamonds is analysed. Find the probability that less than 81% of the sample diamonds fail to qualify as gemstone grade
(Multiple Choice)
A public relations firm found that only 88% of voters in a certain state are satisfied with their state representative. How large a sample of voters should be drawn so that the sample proportion $\hat { p }$ of voters who are satisfied with their representative is approximately normally distributed?
(Multiple Choice)
Use the normal approximation to find the indicated probability. The sample size is n , the population proportion of successes is p , and X is the number of successes in the sample. $n = 76 , p = 0.45 : P ( 26 < X < 36 )$
(Multiple Choice)
For a particular diamond mine, 80% of the diamonds fail to qualify as "gemstone grade". A random sample of 113 diamonds is analysed. Find the mean
(Multiple Choice)
At a cell phone assembly plant, 83% of the cell phone keypads pass inspection. A random sample of 192 keypads is analysed. Find the probability that less than 86% of the sample keypads pass inspection
(Multiple Choice)
Use the normal approximation to find the indicated probability. The sample size is n, the population proportion of successes is p, and X is the number of successes in the sample. $n = 103 , p = 0.62 : P ( X \geq 61 )$
(Multiple Choice)
For a particular diamond mine, 82% of the diamonds fail to qualify as "gemstone grade". A random sample of 90 diamonds is analysed. Find the probability that the proportion of the sample diamonds that fail to qualify as gemstone grade is between 0.78 and 0.88.
(Multiple Choice)
Use the normal approximation to find the indicated probability. The sample size is n , the population proportion of successes is p , and X is the number of successes in the sample. $n = 96 , p = 0.42 : P ( X > 45 )$
(Multiple Choice)
A public relations firm found that only 9 % of voters in a certain state are satisfied with their U.S. senators. How large a sample of voters should be drawn so that the sample proportion $\hat { p }$ of voters who are satisfied with their senators is approximately normally distributed?
(Multiple Choice)
At a cell phone assembly plant, 80 % of the cell phone keypads pass inspection. A random sample of 116 keypads is analysed. Find the mea
(Multiple Choice)
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