The following output from MINITAB presents the results of a hypothesis test.
Test of mu=36 vs. not =36
The assumed standard deviation 12.1
N 52 Mean 39.08 SE Mean 1.97002895% CI (1.55816684,9.280675)Z1.835553 P 0.066424
What are the null and alternate hypotheses?
A) H0:μ=36,H1:μ=36
B) H0:μ=36,H1:μ=39.08
C) H0:μ=39.08,H1:μ=39.08
D) H0:μ=36,H1:μ=36