Simplify.
-$$\frac { x ^ { 3 } + 10 x ^ { 2 } + 21 x } { x ^ { 2 } + 12 x + 35 }$$
A) $\frac { x + 3 } { x + 5 }$
B) $\frac { x ^ { 3 } + 10 x ^ { 2 } + 21 x } { x ^ { 2 } + 12 x + 35 }$
C) $\frac { x ( x + 3 ) } { x + 5 }$
D) $\frac { x + 3 } { x ( x + 5 ) }$

Question

Quizplus · Accepted Answer

First, factor both the numerator and the denominator. The numerator $x^3 + 10x^2 + 21x$ can be factored as $x(x^2 + 10x + 21)$, which further factors to $x(x + 7)(x + 3)$. The denominator $x^2 + 12x + 35$ factors into $(x + 7)(x + 5)$. After canceling the common factor $(x + 7)$, the simplified form is $\frac{x(x + 3)}{x + 5}$.

Simplify - x3+10x2+21xx2+12x+35\frac { x ^ { 3 } + 10 x ^ { 2 } + 21 x } { x ^ { 2 } + 12 x + 35 }x2+12x+35x3+10x2+21x​

Simplify
- $\frac { x ^ { 3 } + 10 x ^ { 2 } + 21 x } { x ^ { 2 } + 12 x + 35 }$