Simplify.
-$\frac { 7 a ^ { 2 } b ( a + 4 b ) } { 28 a b ^ { 2 } }$
A) $\frac { a ( a + 4 b ) } { 4 b }$
B) $\frac { a } { 4 b }$
C) $\frac { a b ( a + 4 b ) } { 4 }$
D) $\frac { ( a + 4 b ) } { 4 a b }$

Question

Quizplus · Accepted Answer

The expression simplifies by canceling common factors in the numerator and denominator. Divide both the numerator and denominator by $7ab$, resulting in $\frac { a ( a + 4 b ) } { 4 b }$.

Simplify - 7a2b(a+4b)28ab2\frac { 7 a ^ { 2 } b ( a + 4 b ) } { 28 a b ^ { 2 } }28ab27a2b(a+4b)​

Simplify
- $\frac { 7 a ^ { 2 } b ( a + 4 b ) } { 28 a b ^ { 2 } }$