Question 1

Medicare would like to test the hypothesis that the standard deviation for the monthly rate for a one- bedroom assisted- living facility is more than $400. The correct hypothesis statement would be ______. A)H₀: a² c 160,000; H₁: a² > 160,000 B)H₀: µ = 160,000; H₁: µ × 160,000 C)H₀: a² c 400; H₁: a² > 400 D)H₀: a c 400; H₁: a > 400

Accepted Answer

A

Question 2

Travelocity would like to test if the standard deviation for roundtrip airfares between New York and London is less than $200. The correct hypothesis statement would be _____. A)H₀: a² = 200; H₁: a² × 200 B)H₀: µ c 200; H₁: µ < 200 C)H₀: a² c 40,000; H₁: a² < 40,000 D)H₀: a c 40,000; H₁: a < 40,000

Accepted Answer

The standard deviation is denoted by the Greek letter sigma (σ), so the correct hypothesis statement is H₀: σ² ≤ 40,000; H₁: σ² < 40,000.

Question 3

YouTube would like to test the hypothesis that the standard deviation for the length of an online video watched by a user is more than 2 minutes. The correct hypothesis statement would be . A)H₀: a² c 4.0; H₁: a² > 4.0 B)H₀: µ c 4.0; H₁: µ < 4.0 C)H₀: a² = 2.0; H₁: a² × 2.0 D)H₀: a²= 4.0; H₁: a² × 4.0

Accepted Answer

The correct hypothesis for testing if the standard deviation is more than 2 minutes involves setting the null hypothesis ($H_0$) to the standard deviation ($\sigma$) equal to 2 minutes and the alternative hypothesis ($H_1$) to the standard deviation greater than 2 minutes. Option A correctly represents this with $\sigma^2 = 4$ (since variance $\sigma^2$ is the square of the standard deviation $\sigma$, and $2^2 = 4$) for the null hypothesis and $\sigma^2 > 4$ for the alternative hypothesis.

Question 4

A golfer would like to test the hypothesis that the variance of his golf score equals 10.0. A random sample of 28 rounds of golf had a sample standard deviation of 3.5. Using α = 0.10, the lower critical value for this hypothesis test would be ______.
A)12.401
B)16.151
C)13.848
D)17.334

Accepted Answer

The answer of A golfer would like to test the...

Question 5

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics exam has a standard deviation that is less than 5.0 minutes. A random sample of 15 students was selected and the sample standard deviation for the time needed to complete the exam was found to be 4.0 minutes. The test statistic for this hypothesis test would be _______.
A)8.96
B)17.67
C)13.61
D)10.42

Accepted Answer

The test statistic for testing a hypothesis about a population standard deviation is calculated using the chi-square distribution: χ² = (n-1)(s²/σ²), where n is the sample size, s is the sample standard deviation, and σ is the hypothesized population standard deviation. Here, χ² = (15-1)(4.0²/5.0²) = 8.96.

Question 6

YouTube would like to test the hypothesis that the standard deviation for the length of an online video watched by a user is more than 2 minutes. A random sample of 21 people who watched online videos was selected. The sample standard deviation for the length of the video was found to be 2.5 minutes. The degrees of freedom for this hypothesis test would be _______.
A)21
B)20
C)18
D)19

Accepted Answer

The degrees of freedom for a hypothesis test concerning the standard deviation or variance is calculated as the sample size minus one. Therefore, with a sample size of 21, the degrees of freedom would be 21 - 1 = 20.

Question 7

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics exam has a standard deviation that is less than 5.0 minutes. The correct hypothesis statement would be _. A)H₀: a2 c 25; H₁: a2 < 25 B)H₀: a = 5; H₁: a × 5 C)H₀: a² = 5; H₁: a² × 5 D)H₀: µ c 5; H₁: µ < 5

Accepted Answer

The correct hypothesis for testing if the standard deviation of the time taken to complete an exam is less than 5 minutes involves comparing the variance (standard deviation squared) to a value. The null hypothesis (H0) posits no difference or the standard deviation being equal to or greater than 5, which translates to the variance (σ^2) being equal to or greater than 25. The alternative hypothesis (H1) suggests the variance is less than 25, which corresponds to a standard deviation of less than 5 minutes.

Question 8

A golfer would like to test the hypothesis that the variance of his golf score equals 10.0. The correct hypothesis statement would be . A)H₀: a = 10.0; H₁: a × 10.0 B)H₀: a² c 10.0; H₁: a² > 10.0 C)H₀: a² = 10.0; H₁: a² × 10.0 D)H₀: µ = 10.0; H₁: µ × 10.0

Accepted Answer

The correct hypothesis for testing if the variance equals a specific value involves stating the null hypothesis (H0) as the variance (σ^2) being equal to the value in question, and the alternative hypothesis (H1) as the variance not equal to that value. Choice C correctly uses σ^2 to denote variance and states the hypotheses appropriately for testing variance, despite the symbols being represented in a non-standard format.

Question 9

Entertainment Software Association would like to test if the standard deviation for the age of "gamers" (those that routinely play video games)is equal to 6.0 years. The correct hypothesis statement would be . A)H₀: µ = 6.0; H₁: µ × 6.0 B)H₀: a² c 6.0; H₁: a² > 6.0 C)H₀: a² = 36.0; H₁: a² × 36.0 D)H₀: a = 6.0; H₁: a × 6.0

Accepted Answer

The null hypothesis should state that the variance (standard deviation squared) is equal to 36.0 (since 6.0 squared is 36.0), and the alternative hypothesis should state that it is not equal to 36.0.

Question 10

Medicare would like to test the hypothesis that the standard deviation for the monthly rate for a one- bedroom assisted- living facility is more than $400. A random sample of 17 assisted living facilities had a standard deviation of $530. The degrees of freedom for this hypothesis test would be _____.
A)17
B)18
C)16
D)19

Accepted Answer

The degrees of freedom for a hypothesis test regarding the standard deviation or variance is calculated as the sample size minus one. Therefore, with a sample size of 17, the degrees of freedom would be 17 - 1 = 16.

Question 11

Medicare would like to test the hypothesis that the standard deviation for the monthly rate for one- bedroom assisted- living facility is more than $400. A random sample of 17 assisted living facilities had a standard deviation of $530. Using α = 0.01, the critical value for this hypothesis test would be ______.
A)34.267
B)6.908
C)32.000
D)5.812

Accepted Answer

The answer of Medicare would like to test the hypothesis...

Question 12

A retail chain would like to test if a difference exists between the variability of customer satisfaction scores from two locations. The following data represents satisfaction scores from a random sample of customers from these locations on a scale of 1- 20.
$$\begin{array} { | l | l | l | l | l | l | l | l | } 
\hline \text { Location 1 } & 12 & 14 & 20 & 18 & 15 & 17 & 16 \
\hline \text { Location 2 } & 18 & 19 & 17 & 18 & 16 & 20 & \
\hline
\end{array}$$
Using ?=0.10, the critical value for this hypothesis test would be _____
A)6.094
B)5.343
C)4.950
D)3.405

Accepted Answer

The answer of A retail chain would like to test...

Question 13

Travelocity would like to test if the standard deviation for roundtrip airfares between New York and London is less than $200. A random sample of 22 roundtrip airfares between New York and London had a standard deviation of $142. The degrees of freedom for this hypothesis test would be _______.
A)20
B)19
C)21
D)18

Accepted Answer

The degrees of freedom for a hypothesis test involving the standard deviation or variance is calculated as the sample size minus one. Therefore, for a sample size of 22, the degrees of freedom would be 22 - 1 = 21.

Question 14

YouTube would like to test the hypothesis that the standard deviation for the length of an online video watched by a user is more than 2 minutes. A random sample of 21 people who watched online videos was selected. The sample standard deviation for the length of the video was found to be 2.5 minutes. The test statistic for this hypothesis test would be _____.
A)22.60
B)31.25
C)10.19
D)4.66

Accepted Answer

The answer of YouTube would like to test the hypothesis...

Question 15

Entertainment Software Association would like to test if the standard deviation for the age of "gamers" (those that routinely play video games)is equal to 6.0 years. The standard deviation for the age from a random sample of 24 gamers is 3.8 years. The test statistic for this hypothesis test would be ______.
A)45.61
B)9.23
C)24.33
D)31.82

Accepted Answer

The test statistic for testing if the standard deviation of a population is equal to a specific value (σ0) can be calculated using the formula: $\chi^2 = \frac{(n-1)s^2}{\sigma_0^2}$, where $n$ is the sample size, $s$ is the sample standard deviation, and $\sigma_0$ is the hypothesized population standard deviation. Here, $n=24$, $s=3.8$, and $\sigma_0=6.0$. Plugging these values into the formula gives $\chi^2 = \frac{(24-1)(3.8)^2}{(6.0)^2} = 9.23$.

Question 16

Entertainment Software Association would like to test if the standard deviation for the age of "gamers" (those that routinely play video games)is equal to 6.0 years. The standard deviation for the age from a random sample of 24 gamers is 3.8 years. Using α = 0.05, the lower critical value for this hypothesis test would be ______.
A)11.689
B)10.235
C)13.477
D)12.750

Accepted Answer

The lower critical value for a one-tailed hypothesis test with α = 0.05 and 23 degrees of freedom (n-1) is 11.689.

Question 17

A golfer would like to test the hypothesis that the variance of his golf score equals 10.0. A random sample of 28 rounds of golf had a sample standard deviation of 3.5. The degrees of freedom for this hypothesis test would be _______.
A)27
B)24
C)25
D)26

Accepted Answer

The degrees of freedom for a variance or standard deviation hypothesis test is calculated as the sample size minus one. Here, with a sample size of 28, the degrees of freedom would be 28 - 1 = 27.

Question 18

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics exam has a standard deviation that is less than 5.0 minutes. A random sample of 15 students was selected and the sample standard deviation for the time needed to complete the exam was found to be 4.0 minutes. Using α = 0.05, the conclusion for this hypothesis test would be that because the test statistic is
A)more than the critical value, we fail to reject the null hypothesis and conclude that the standard deviation for the time to complete an exam is less than 5.0 minutes.
B)less than the critical value, we fail to reject the null hypothesis and cannot conclude that the standard deviation for the time to complete an exam is less than 5.0 minutes.
C)less than the critical value, we reject the null hypothesis and cannot conclude that the standard deviation for the time to complete an exam is less than 5.0 minutes.
D)more than the critical value, we fail to reject the null hypothesis and cannot conclude that the standard deviation for the time to complete an exam is less than 5.0 minutes.

Accepted Answer

The correct interpretation of the hypothesis test outcome when the test statistic is more than the critical value is that we fail to reject the null hypothesis. However, failing to reject the null hypothesis does not allow us to conclude that the standard deviation is less than 5.0 minutes; it simply means there is not enough evidence to support the alternative hypothesis that the standard deviation is less than 5.0 minutes.

Question 19

Travelocity would like to test if the standard deviation for roundtrip airfares between New York and London is less than $200. A random sample of 22 roundtrip airfares between New York and London had a standard deviation of $142. The test statistic for this hypothesis test would be ______.
A)8.67
B)7.03
C)13.36
D)10.59

Accepted Answer

The answer of Travelocity would like to test if the...

Question 20

Medicare would like to test the hypothesis that the standard deviation for the monthly rate for a one- bedroom assisted- living facility is more than $400. A random sample of 17 assisted living facilities had a standard deviation of $530. The test statistic for this hypothesis test would be ________.
A)28.09
B)15.06
C)19.72
D)24.56

Accepted Answer

The test statistic for this hypothesis test would be 28.09. This is calculated by dividing the sample standard deviation by the hypothesized standard deviation: 530 / 400 = 28.09.

Quiz 13: Violence and Unintentional Injuries

Medicare would like to test the hypothesis that the standard deviation for the monthly rate for a one- bedroom assisted- living facility is more than $400. The correct hypothesis statement would be ______.

Travelocity would like to test if the standard deviation for roundtrip airfares between New York and London is less than $200. The correct hypothesis statement would be _____.

YouTube would like to test the hypothesis that the standard deviation for the length of an online video watched by a user is more than 2 minutes. The correct hypothesis statement would be .

A golfer would like to test the hypothesis that the variance of his golf score equals 10.0. A random sample of 28 rounds of golf had a sample standard deviation of 3.5. Using α = 0.10, the lower critical value for this hypothesis test would be ______.

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics exam has a standard deviation that is less than 5.0 minutes. The correct hypothesis statement would be _.

A golfer would like to test the hypothesis that the variance of his golf score equals 10.0. The correct hypothesis statement would be .

Entertainment Software Association would like to test if the standard deviation for the age of "gamers" (those that routinely play video games) is equal to 6.0 years. The correct hypothesis statement would be .

Travelocity would like to test if the standard deviation for roundtrip airfares between New York and London is less than $200. A random sample of 22 roundtrip airfares between New York and London had a standard deviation of $142. The degrees of freedom for this hypothesis test would be _______.

A golfer would like to test the hypothesis that the variance of his golf score equals 10.0. A random sample of 28 rounds of golf had a sample standard deviation of 3.5. The degrees of freedom for this hypothesis test would be _______.

Travelocity would like to test if the standard deviation for roundtrip airfares between New York and London is less than $200. A random sample of 22 roundtrip airfares between New York and London had a standard deviation of $142. The test statistic for this hypothesis test would be ______.