-The transistor amplifier in Figure has the following values: hie = 2 kΩ, hfe = 120, Cbc = 5 pF, Cbe = 10 pF, RS = 300 Ω, Rth = 1.2 kΩ, rc = 4 kΩ, and Cin = 1200 pF. What is the value if f2C for the circuit?
A) 16.54 kHz
B) 33.02 kHz
C) 330 kHz
D) 7.958 MHz

Question

-The transistor amplifier in Figure has the following values: hie = 2 kΩ, hfe = 120, Cbc = 5 pF, Cbe = 10 pF, RS = 300 Ω, Rth = 1.2 kΩ, rc = 4 kΩ, and Cin = 1200 pF. What is the value if f2C for the circuit?
A) 16.54 kHz 
B) 33.02 kHz 
C) 330 kHz 
D) 7.958 MHz

Quizplus · Accepted Answer

The cutoff frequency f2C can be calculated using the formula for the high-frequency response of a transistor amplifier. The dominant pole is determined by the total capacitance at the input and output. Given the values, the calculation results in approximately 33.02 kHz.

-The Transistor Amplifier in Figure Has the Following Values: Hie