$\int \frac{7+x}{\sqrt{x}} d x=14 \sqrt{x}+\frac{2}{3} x^{\frac{3}{2}}+C$ .

Name: $\int \frac{7+x}{\sqrt{x}} d x=14 \sqrt{x}+\frac{2}{3} x^{\frac{3}{2}}+C$ .
Brand: Quizplus
Rating: 4.9 (37 reviews)

Question

Quizplus · Accepted Answer

The integral $\int \frac{7+x}{\sqrt{x}} d x$ can be split into $\int 7x^{-\frac{1}{2}} dx + \int x^{\frac{1}{2}} dx$, which simplifies to $14\sqrt{x} + \frac{2}{3}x^{\frac{3}{2}} + C$, matching the given expression.

∫7+xxdx=14x+23x32+C\int \frac{7+x}{\sqrt{x}} d x=14 \sqrt{x}+\frac{2}{3} x^{\frac{3}{2}}+C∫x​7+x​dx=14x​+32​x23​+C

$\int \frac{7+x}{\sqrt{x}} d x=14 \sqrt{x}+\frac{2}{3} x^{\frac{3}{2}}+C$