$\int \sqrt{1-5 x} d x=-\frac{2}{15}(1-5 x)^{\frac{3}{2}}+C$ .

Name: $\int \sqrt{1-5 x} d x=-\frac{2}{15}(1-5 x)^{\frac{3}{2}}+C$ .
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Question

Quizplus · Accepted Answer

The integral of $\sqrt{1-5x}$ with respect to $x$ is $-\frac{2}{15}(1-5x)^{\frac{3}{2}} + C$, using substitution and the power rule for integration.

∫1−5xdx=−215(1−5x)32+C\int \sqrt{1-5 x} d x=-\frac{2}{15}(1-5 x)^{\frac{3}{2}}+C∫1−5x​dx=−152​(1−5x)23​+C