Find $\int \frac{1}{x^{2}+3 x-10} d x$ .
A) $-\frac{1}{10}(\ln |x+5|+\ln |x-2|)+C$
B) $\frac{1}{7}(\ln |x+5|+\ln |x-2|)+C$
C) $\frac{1}{10}(\ln |x+5|-\ln |x-2|)+C$
D) $-\frac{1}{7}(\ln |x+5|-\ln |x-2|)+C$

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The Answer of Find $\int \frac{1}{x^{2}+3 x-10} d x$ .
A) $-\frac{1}{10}(\ln |x+5|+\ln |x-2|)+C$
B) $\frac{1}{7}(\ln |x+5|+\ln |x-2|)+C$
C) $\frac{1}{10}(\ln |x+5|-\ln |x-2|)+C$
D) $-\frac{1}{7}(\ln |x+5|-\ln |x-2|)+C$

Find ∫1x2+3x−10dx\int \frac{1}{x^{2}+3 x-10} d x∫x2+3x−101​dx A) −110(ln⁡∣x+5∣+ln⁡∣x−2∣)+C-\frac{1}{10}(\ln |x+5|+\ln |x-2|)+C−101​(ln∣x+5∣+ln∣x−2∣)+C B) 17(ln⁡∣x+5∣+ln⁡∣x−2∣)+C\frac{1}{7}(\ln |x+5|+\ln |x-2|)+C71​(ln∣x+5∣+ln∣x−2∣)+C

Find $\int \frac{1}{x^{2}+3 x-10} d x$
A) $-\frac{1}{10}(\ln |x+5|+\ln |x-2|)+C$ B) $\frac{1}{7}(\ln |x+5|+\ln |x-2|)+C$