Suppose that as a storm dies down, its rainfall rate (in inches/hour)is given by $y=\frac{1}{0.09+t^{2}}$ for 0 $\le$ t $\le$ 2, where t is the number of hours since the point of heaviest rainfall.What is the average rainfall rate over these two hours? Round your answer to 3 decimal places.

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The Answer of Suppose that as a storm dies down, its rainfall rate (in inches/hour)is given by $y=\frac{1}{0.09+t^{2}}$ for 0 $\le$ t $\le$ 2, where t is the number of hours since the point of heaviest rainfall.What is the average rainfall rate over these two hours? Round your answer to 3 decimal places.

Suppose That as a Storm Dies Down, Its Rainfall Rate y=10.09+t2y=\frac{1}{0.09+t^{2}}y=0.09+t21​

Suppose That as a Storm Dies Down, Its Rainfall Rate $y=\frac{1}{0.09+t^{2}}$