Balance the following equation for the combustion of benzene: C₆H₆(l) + O₂(g) $\to$ H₂O(g) + CO₂(g) A) C₆H₆(l) + 9O₂(g) $\to$ 3H₂O(g) + 6CO₂(g) B) C₆H₆(l) + 9O₂(g) $\to$6H₂O(g) + 6CO₂(g) C) 2C₆H₆(l) + 15O₂(g) $\to$ 6H₂O(g) + 12CO₂(g) D) C₆H₆(l) + 15O₂(g) $\to$ 3H₂O(g) + 6CO₂(g) E) 2C₆H₆(l) + 9O₂(g) $\to$6H₂O(g) + 12CO₂(g)

Question

Quizplus · Accepted Answer

The balanced equation for the combustion of benzene is 2C6H6(l) + 15O2(g) → 6H2O(g) + 12CO2(g), ensuring that the number of each type of atom is equal on both sides of the equation.

Balance the Following Equation for the Combustion of Benzene →\to→ H2O(g) + CO2(g) A) C6H6(l) + 9O2(g)

Balance the Following Equation for the Combustion of Benzene $\to$ H₂O(g) + CO₂(g)
A) C₆H₆(l) + 9O₂(g)