Ammonia will react with fluorine to produce dinitrogen tetrafluoride and hydrogen fluoride (used in production of aluminum, in uranium processing, and in frosting of light bulbs) . 2NH₃(g) + 5F₂(g) $\to$ N₂F₄(g) + 6HF(g)
How many moles of NH₃are needed to react completely with 13.6 mol of F₂?

Question

Ammonia will react with fluorine to produce dinitrogen tetrafluoride and hydrogen fluoride (used in production of aluminum, in uranium processing, and in frosting of light bulbs) . 2NH₃(g) + 5F₂(g)

\to

N₂F₄(g) + 6HF(g)
How many moles of NH₃are needed to react completely with 13.6 mol of F₂?

Quizplus · Accepted Answer

According to the balanced equation, the mole ratio between NHS and F is 2:5. Therefore, for every 2 moles of NHS, we need 5 moles of F. To find out how many moles of NHS are needed to react with 13.6 mol of F, we can set up a proportion:

2 mol NHS / 5 mol F = x mol NHS / 13.6 mol F

Cross-multiplying, we get:

2 mol NHS × 13.6 mol F = 5 mol F × x mol NHS

Simplifying:

x = (2 mol NHS × 13.6 mol F) / 5 mol F = 5.44 mol NHS

Therefore, the correct answer is D: 5.44 mol.

Ammonia Will React with Fluorine to Produce Dinitrogen Tetrafluoride and Hydrogen