$$\text { If } Z = \sqrt { R ^ { 2 } + X ^ { 2 } } , \text { where } R = 3,300 \text { and } X = 4,700 , \text { then } Z =$$
A)1,939
B)5,743
C)8,000
D)969

Name: \[\text { If } Z = \sqrt { R ^ { 2 } + X ^ { 2 } } , \text { where } R = 3,300 \text { and } X = 4,700 , \text { then } Z =\] A)1,939 B)5,743 C)8,000 D)969
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Quizplus · Accepted Answer

Using the Pythagorean theorem. 
$Z = \sqrt{R^2+X^2} = \sqrt{3300^2 + 4700^2} \approx 5742.64 \approx 5,743$ (rounded to the nearest whole number). Therefore, the correct option is B.

If Z=R2+X2, where R=3,300 and X=4,700, then Z=\text { If } Z = \sqrt { R ^ { 2 } + X ^ { 2 } } , \text { where } R = 3,300 \text { and } X = 4,700 , \text { then } Z = If Z=R2+X2​, where R=3,300 and X=4,700, then Z=

$\text { If } Z = \sqrt { R ^ { 2 } + X ^ { 2 } } , \text { where } R = 3,300 \text { and } X = 4,700 , \text { then } Z =$